1 . Assume the regenerating heart prices for a sample of individuals are usually distributed having a mean of 70 and a standard deviation of 12-15. Use the 68-95-99 rule to get the following quantities: a.
Percentage of prices less than seventy = 50 percent b. Percentage of prices less than fifty-five = 16% c. Comparable frequency of rates lower than 40 sama dengan 2 . 5% d. Percentage of prices less than eighty-five = 84% e. Family member frequency of rates lower than 100 = 97. 5% f. Percentage of rates greater than eighty-five = 16% g.
Percentage of prices greater than fifty five = 84% h. Family member frequency of rates more than 40 sama dengan 97. 5% i. Percentage of costs between fifty-five and eighty five = 68% j. Percentage of costs between 75 and 75 = forty seven. 5% 2 . Here are the results of four of your test: | | Your rating | Imply |Standard Change | |Math (out of 100) |70 |80 |3. | |QM (out of 20) |20 |18 |3 | |RM (out of 100) |66 |75 |5 | |History (out of 30) |28 |20 |3. 5 | a. Present all four outcomes on a standardised normal contour. Be sure to present the measurements for each evaluation. Math: (70 , 80) / a few. 3 sama dengan -3. goal *QM: (20 , 18) / 3 = 0. 67 *RM: (66 , 75) / 5 = -1. almost 8 *History: (28 , 20) /3. a few = 2 . 29 [pic] Math RM QM History b. What is the percentage of people who have an improved mark than you in math? My math’s mark is definitely -3. 03 ( 49. 88 is the area between Mean and z. (50% + 49. 88) 99. 88% of folks get a better mark than me in math. c. What is the proportion of people who have a lower indicate than you in RM? I acquired -1. 8 ( 35. 99 (50 , 35. 99) 14. 1% of people have a reduced mark than me in RM m. Which check is the best? Clarify The best evaluation is the Record one, as it has the maximum z-score, 2 . 29. There is a high brilliance between my mark and the mark’s average of the school. I’m 98. 9% within the class. 98. 9% of people got a lower mark than me of all time. 3. Pediatric data disclose that the normal child can be toilet educated at 26 months, yet that there is a 2-month normal deviation using this norm. a. What percentage of children are toilet-trained by 23 months? 50 ” 35. 31) 14. 69% of children will be toilet-trained simply by 23 several weeks. b. A mother is concerned that her son was trained at 30 a few months. What is the probability of having a child getting trained at 30 several weeks? (50 ” 47. 72) 2 . 28% is the possibility of having a kid being skilled at 35 months. c. A mom is delighted that her daughter can be trained by 18 months. How common would it be that a child would be toilet trained at this young age? (50 ” 49. 997) There is. 003 of possibilities that a child would be toiled trained in 18 months. four.
Assume the scores amongst Asian Us citizens on an hysteria scale are typically distributed which has a mean of twenty-two and a normal deviation of two. 5 (higher scores reflect greater emotions of alienation). Based on this distribution, identify a. The probability of the Asian American having an alienation credit score between twenty two and twenty-five The likelihood of an Oriental American having an hysteria score between 22 and 25 can be 38. 49%. b. The probability associated with an Asian American having an alienation score of twenty or fewer. (50 ” 28. 81) The possibility of an Oriental American Having an hysteria score of 20 or perhaps less is 21. 19%.