types of chemical reactions lab article

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Copper (II) sulfate pentahydrate crystals are light blue and granular. After being heated, the crystals turned into a white powder and condensation formed in the upper part of test tube. It is represented by the equation CuSO4•5(H2O)(s) >CuSO4(s) + 5(H2O)(g) When 5 drops of water were added to the white powder, bubbling occurred and the powder turned into a blue liquid, and then into the original blue coloured crystals (copper (II) sulfate pentahydrate). It is represented by the equation CuSO4(s) + 5(H2O)(l) >CuSO4•5(H2O)(s) W Sodium sulfate solution can be described as colourless, translucent liquid.

Barium chloride is a colourless, transparent liquid. After adding a medicine dropper of barium chloride solution, the solution immediately became cloudy and milky looking. A precipitate was formed during the reaction. It is represented by the equation BaCl2(aq) + Na2SO4(aq) >BaSO4(s) + 2NaCl(aq) D Sturdy magnesium is a slightly shiny and comfortable metal. Hydrochloric acid can be described as colourless, transparent liquid. Following adding hydrochloric acid, magnesium (mg) began to fizz, releasing pockets. The bottom in the test pipe got hotter. Condensation produced in the upper part of test out tube and the magnesium viewed white and also much smaller.

The reaction is represented by the equation Mg(s) + 2HCl(aq) >MgCl2(aq) + H2(g) E Potassium iodide is a white granular solid. Hydrogen peroxide is a cooler than air, colourless, transparent liquid. After adding hydrogen peroxide, potassium iodide solids disappeared, followed by bubbling and colour change of solution to yellow, but still transparent. Temperature of solution is still cooler than air. After inserting a glowing splint into the mouth of the test tube, a pop sound is made and the flint is re-ignited. But the flame quickly died. The reaction is represented by the equation 2H2O2(aq) ––KI>2H2O(l) & O2(g)

F The iron nail is a hard, shiny, grey, metal solid. The copper (II) sulfate solution is a light blue, translucent liquid. After the iron nail has been immersed in the copper (II) sulfate solution for a while, it had chunks of reddish brown rust-like substances on it. The reaction is represented by this equation CuSO4(aq) + Fe(s) >FeSO4(aq) & Cu(s) Conclusion Experiment A demonstrated a decomposition effect and a synthesis reaction. The decomposition reaction happened when birdwatcher (II) sulfate pentahydrate was heated. The compound decomposed to copper mineral (II) sulfate and water. The water is definitely the condensation.

Exposure to heat is what caused this product’s decomposition, so it is an endothermic reaction. The reason for this is that for chemical reactions to happen, at the smallest scale, the individual chemical molecules have to bump into one another. As molecules warm up they begin to vibrate more and the chances of them bumping in to one another increases – the more bumps that happen, the faster the reactions go. It is represented by the equation AB >A + B or (in the case of the lab) CuSO4•5(H2O)(s) >CuSO4(s) & 5(H2O)(g) The synthesis effect occurred once water was added to copper mineral (II) sulfate.

The compound synthesized to copper (II) sulfate pentahydrate. Synthesis can occur when one compound or molecule is introduced to another. It is represented by the equation A + B >AB or (in the case of the lab) CuSO4(s) + 5(H2O)(l) >CuSO4•5(H2O)(s) Experiment M demonstrated a double shift reaction/precipitate reaction. The reaction happened when aqueous sodium sulfate and aqueous barium chloride were blended together. The milky medicine is BaSO4, which was a product of the response. The substance is a precipitate because it is absurde (says etc the solubility table).

In double displacement reactions two ionic compounds switch cations. In order to switch cations, the ions must first be separated, in a solution for example, so that they may react with other ions present. A precipitate forms because the combination of a positive and a negative ion in solution forms a compound that is insoluble in water and precipitates out of the solution. The precipitate ions cannot re-dissolve in the mixture so they are rapidly removed from the solution. Double displacement is represented by the equation AB + CD >AD + CB or (in the case of the lab) BaCl2(aq) + Na2SO4(aq) >BaSO4(s) & 2NaCl(aq).

Test D shown a single displacement reaction/exothermic reaction. The reaction took place when hydrochloric acid was added to solid magnesium. Since Mg can be higher than They would on the activity series (more reactive), for that reason Cl ions are more interested in Mg ions and will leave H to bond with Mg. Magnesium is more reactive than They would because it features two electrons in its valence shell, the two of these electrons are lost because they are far from the nucleus (compared to that of H) and so there is less attraction, leading to low ionization energy (energy needed to take out electrons). Magnesium must reduce its exterior electrons to be able to react.

Hydrogen has one particular valence electron and it is nearer to the center (compared to that of Mg) so there may be more fascination, resulting in bigger ionization energy. Therefore it is easier for Magnesium to react (lose electron) compared to They would. The bubbles are H2 gas forming. Heat was released so it is a great exothermic reaction. An exothermic reaction is a chemical reaction that may be accompanied by the release of heat. Basically, the energy required for the reaction to occur is less than the overall energy produced. As a result of this kind of, the extra energy is unveiled, usually in the form of heat. One displacement can be represented by equation.

A + BC >AC + B or perhaps (in the situation of the lab) Mg(s) + 2HCl(aq) >MgCl2(aq) + H2(g) Experiment Electronic is a catalytic decomposition effect. Hydrogen peroxide is an unstable compound that may decompose over time, just on exposure to sun rays or heat (energy), to create water and oxygen gas. It should be retained in an funeste container within a cool environment (hence the cool temperature). The rate of decomposition of hydrogen peroxide can be increased with a catalyst, like potassium iodide, which is a substance that speeds up a chemical reaction yet remains chemically unchanged by the end of the reaction.

The mechanism of catalysis involves the negative iodine ions just. The mechanism is a multi sequence reaction H2O2(aq) & I-(aq)>IO-(aq) + H2O(l) H2O2(aq) + IO-(aq) >I-(aq) + H2O(l) + O2(g) *When the IO ion was performed, it would react with one other H2O2 molecule until there were no more H2O2 molecules still left. The second stage regenerated the negative iodine ion (thus acting as a catalyst). The iodine ions were not afflicted with the reaction, that means it did not bond with any other chemicals other than it had originally (potassium) by the end in the reaction.

The iodine acted as a catalyst, it hasten the reaction devoid of bonding eventually. The potassium did not play any position in the effect, it was simply bonded with iodine in the beginning. In fact , another substance with similar chemical properties while potassium, sodium for example , could have been bonded with iodine ahead of the reaction, and the reaction might have been similar. Decomposition is represented by equation AB >A & B or (in the situation of the lab) 2H2O2(aq) ––KI>2H2O(l) + O2(g) The beautiful splint sprang because it ignited hydrogen gas. But hydrogen gas was not made from the reaction so I presume it was up before.

The hydrogen gas was oxidized, it put together with oxygen gas violently and quickly to create water. The oxidization triggered vibrations which can be the swallowing sound. The splint lso are lit since oxygen gas is also present. The fire perished eventually for the reason that oxygen have been used up inside the test tube. The excellent splint evaluation proved which the above reaction occurred, mainly because when a glowing splint is usually exposed to UNITED KINGDOM gas, this re-ignites and that is what experienced happened, it is a complete combustion because there was an excess of O2 gas. Experiment F can be described as single shift reaction/precipitate effect.

The reaction happened when iron and copper (II) sulfate came into get in touch with. Since Confianza is more than Cu for the activity series, therefore SO4 molecules are usually more attracted to Ideolog�a ions and definitely will leave Cu to connection with Fe. The medicine created can be copper, which in turn collects on the nail. Single displacement effect is symbolized by the equation A & BC >AIR CONDITIONING UNIT + B or (in the case with the lab) CuSO4(aq) + Fe(s) >FeSO4(aq) & Cu(s) Problems 1 . Following heating water piping (II) pentahydrate, we would not allow the check tube to cool down totally before adding water. When water was added this began to steam and escape.

This could include changed the results because we do not find out if the evaporation took away substances from the check tube, and so some substances that should be there can be missing. This will give us erroneous results. 2 . We may have handled the magnesium remove and the iron nail intended for too long. Contaminants on the outer skin such as natural oils or additional chemicals could become residue on the magnesium (mg) and straightener and respond in the test, which would give us erroneous results (shouldn’t have happened). 3. There are people going for walks by the bunsen burner. Wind that all their movement produced may have affected the temperature of flame and therefore the effects.


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